Given: - \( m_1 = 10 \, \text{kg} \) (on incline) - \( m_2 = 15 \, \text{kg} \) (hanging) - \( \theta = 30^\circ \) Inclined mass: \( F_{\text{incline}} = m_1 g \sin(\theta) = 10g \cdot 0.5 = 5g\) Hanging mass: \(F_{\text{weight}} = m_2 g = 15g\) Net Force: \(F_{\text{net}} = F_{\text{weight}} - F_{\text{incline}} = 15g - 5g = 10g\) Total Mass \(m_{\text{total}} = m_1 + m_2 = 25 \, \text{kg}\) Using \( F_{\text{net}} = m_{\text{total}} \cdot a \): \(10g = 25a \quad \Rightarrow \quad a = \frac{10g}{25} = \frac{2g}{5}\) The acceleration is: \(a = \frac{2g}{5} \, \text{m/s}^2\)