The latent heat of fusion of ice is 80cal g\(^{-1}\). How much heat is required to change 10g of ice at 0ºC into water at the same temperature?
A
80 cal
B
10 cal
C
8 cal
D
800 cal
E
400 cal
Verified Correct Answer: D.
Physical Principles & Numerical Solution
Quantity of heat = ml
= 10 x 80
= 800 cal
Source: Myschool Past Questions Archive (Record #29269)