A piece of rubber 10cm long stretches 6mm when a load of 100N is hung from it. What is the strain?
A
60
B
6
C
6 x 10-2
D
6 x 10-3
E
0.6
Verified Correct Answer: C.
Physical Principles & Numerical Solution
Strain = \(\frac{\Delta L}{L}\)
Extension produced = 6mm or 0.6cm
Original length = 10cm
= \(\frac{0.6}{10}\)
= 0.06 or 6 x 10\(^{-2}\)
Source: Myschool Past Questions Archive (Record #29235)