If in a simple pendulum experiment the length of the inextensible string is increased by a factor of four, its period is increased by a factor of
A
4
B
\(\frac{\pi}{2}\)
C
\(\frac{1}{4}\)
D
2\(\pi\)
E
2
Verified Correct Answer: E.
Physical Principles & Numerical Solution
In simple pendulum, T = 2\(\pi\)\(\sqrt\frac{L}{g}\)
\(\frac{T_2}{T_1}\) = \(\sqrt\frac{L_1}{L_2}\) but, L2 = 4L1
\(\frac{T_2}{T_1}\) = \(\sqrt\frac{L_1}{4L_1}\)
T2 = 4T1
Source: Myschool Past Questions Archive (Record #29168)