A 500kg car which was initially at rest travelled with an acceleration of 5m sec-2, its kinetic energy after 4 seconds was
A
105J
B
2.5 x 103J
C
2 x 103J
D
5 x 103J
E
5 x 105J`
Verified Correct Answer: A.
Physical Principles & Numerical Solution
K.E = \(\frac{1}{2}\)mv2; m (at + u)2
since, v = at + u = \(\frac{1}{2}\) x 500 [(5 x 4)+ 0]2
= 105J
Source: Myschool Past Questions Archive (Record #29160)