A milliameter of resistance 5\(\Omega\) and full scale deflection of 50m A is to used to measure a potential difference of 50 V. The resistance of the multiplier should be
A
95\(\Omega\)
B
110\(\Omega\)
C
595\(\Omega\)
D
995\(\Omega\)
E
1005\(\Omega\)
Verified Correct Answer: D.
Physical Principles & Numerical Solution
V = IR
50 = 50 x 10\(^{-3}\) (5 + R)
R = 995\(\Omega\)
Source: Myschool Past Questions Archive (Record #29104)