A cell of e.m.f 2V and internal resistance 1\(\Omega\) supplies a current of 0.5 amps to a resistance whose value is
A
0.5\(\Omega\)
B
1\(\Omega\)
C
2\(\Omega\)
D
2.5\(\Omega\)
E
3\(\Omega\)
Verified Correct Answer: E.
Physical Principles & Numerical Solution
1 = \(\frac{E}{R + r}\)
\(\frac{2}{R + 1}\) = 0.5
0.5R = 2 - 0.5 = 1.5
R = \(\frac{1.5}{0.5}\)
= 3\(\Omega\)
Source: Myschool Past Questions Archive (Record #28992)