An electric iron is rated at 1000watts, 250v. The corresponding maximum resistance and accompanying current is
A
62.5A, 4.0\(\Omega\)
B
16.0A, 62.5\(\Omega\)
C
62.5A, 16.0\(\Omega\)
D
4.0A, 62.5\(\Omega\)
E
4.0A, 250\(\Omega\)
Verified Correct Answer: D.
Physical Principles & Numerical Solution
R = \(\frac{V^2}{R}\) = IV ; R = \(\frac{V^2}{P}\) and I = \(\frac{P}{V}\)
R = \(\frac{(250)^2}{100}\) and I = R = \(\frac{1000}{250}\)
R = 62.5\(\Omega\) and I = 4A
Source: Myschool Past Questions Archive (Record #28896)