The hatch door of a submarine has an area of 0.5m2. The specific gravity of sea water is 1.03. Assume that g = 10ms-1,and neglect the atmospheric pressure. The force exerted by the sea water on the hatch door at a depth of 200m is
A
1.03 x 105N
B
1.03 x 104Nm-2
C
1.06 x 105Nm-2
D
2.06 x 106N
E
1.03 x 103N
Verified Correct Answer: E.
Physical Principles & Numerical Solution
Pressure in liquid = e x h x g
Pressure in solid = \(\frac{force}{area}\)
\(\frac{force}{area}\) = e x h x g
force = 0.5 x 10 x 200 x 1.03
= 1030N
Source: Myschool Past Questions Archive (Record #28887)