If the force of a charge of 0.2 coulomb in an electric field is 4N, then the electric field intensity of the field is
A
0.8
B
0.8N/C
C
20.0N/C
D
4.2N/C
Verified Correct Answer: C.
Physical Principles & Numerical Solution
Field intensity = \(\frac{force}{charge}\)
\(\frac{4}{0.2}\) = 20N/C
Source: Myschool Past Questions Archive (Record #28883)