To find the internal resistance of the cell, we can use the formula: \(V = E - I r\) Where: - \( V \) = terminal voltage (2 V) - \( E \) = electromotive force (emf) of the cell (2.2 V) - \( I \) = current through the circuit - \( r \) = internal resistance of the cell {Step 1: Calculate the Current} Using Ohm's law, the current (\( I \)) flowing through the resistor is given by: \(I = \frac{V}{R}\) Where: - \( V = 2 \, \text{V} \) (terminal voltage) - \( R = 4 \, \Omega \) Thus, \(I = \frac{2 \, \text{V}}{4 \, \Omega} = 0.5 \, \text{A}\) {Step 2: Substitute Values into the Formula} Now substituting \( I \), \( V \), and \( E \) into the formula: \(2 = 2.2 - 0.5 r\) {Step 3: Solve for Internal Resistance \( r \)} Rearranging the equation gives: \(0.5 r = 2.2 - 2\) \(0.5 r = 0.2\) \(r = \frac{0.2}{0.5} = 0.4 \, \Omega\) Thus, the internal resistance of the cell is: \(\boxed{0.4 \, \Omega}\)