If the pressure on 100cm3 of an ideal gas is doubled while its kelvin temperature is halved, then the new volume of the gas will become
A
25cm3
B
50cm3
C
100cm3
D
200cm3
E
400cm3
Verified Correct Answer: A.
Physical Principles & Numerical Solution
\(\frac{P_1V_1}{T_1}\) = \(\frac{P_2V_2}{T_2}\)
P\(_2\) = 2P\(_1\) ; T\(_1\) = 2T\(_2\)
V\(_2\) = \(\frac{P_1 \times V_1 \times T_2}{T_1 \times P_2}\) = \(\frac{P_1 \times 100 \times T_2}{2T_2 \times 2P_1}\) = \(\frac{100}{4}\)
= 25cm\(^3\)
Source: Myschool Past Questions Archive (Record #28833)