The distance travelled by a particle starting from rest is plotted against the square of the time elapsed from the commencement of motion. The resulting graph is linear, the slope of this graph is a measure of
A
initial displacement
B
initial velocity
C
acceleration
D
half the acceleration
E
half the initial velocity
Verified Correct Answer: D.
Physical Principles & Numerical Solution
The slope of the graph of distance versus time squared is equal to \(\frac{1}{2}\)a, which means the slope measures half the acceleration.
Also from s = ut + \(\frac{1}{2}\)at\(^2\)
when u = 0 then, s = \(\frac{1}{2}\)at\(^2\)
So, \(\frac{\Delta\text{s}}{\Deltat^2}\) = \(\frac{1}{2}\)a
Source: Myschool Past Questions Archive (Record #28664)