If the distance between two stationary charged particle is doubled, the magnitude of the electro-static force between them will be
A
doubled
B
halved
C
a quarter of its former value
D
unchanged
E
four times the original value
Verified Correct Answer: C.
Physical Principles & Numerical Solution
F \(\alpha\) \(\frac{1}{d^2}\)
F x d2 = constant
F1 x (d1)2 = F2 x (d2)2
d2 = 2d1
F1 x (d1)2 = F2 x (2d1)2
F2 = \(\frac{1}{4}\)F1
Source: Myschool Past Questions Archive (Record #28639)