Two liquids, P at a temperature of 20oC and Q at a temperature of 80oC have specific heat capacities of 1.0Jkg-1oC-1 and 1.5J kg-1 oC-1respectively. if equal masses of P and Q are mixed in a lagged calorimeter, then the equilibrium temperature is
A
44oC
B
50oC
C
56oC
D
60oC
E
70oC
Verified Correct Answer: C.
Physical Principles & Numerical Solution
Heat lost = heat gained
m x (80 - \(\theta\)) x 1.5 = m x (\(\theta\) - 20) x 1
\(\theta\) = 56oC
Source: Myschool Past Questions Archive (Record #28585)