A simple pendulum with a period of 2.0s has its length doubled. Its new period is
A
1.00s
B
1.41s
C
0.3s
D
2.83s
E
4.00s
Verified Correct Answer: D.
Physical Principles & Numerical Solution
Using \(\frac{T_1}{T_2}\) = \(\sqrt\frac{L_1}{L_2}\)
\(\frac{2}{T_2}\) = \(\sqrt\frac{L_1}{2L_1}\)
T2 = 2.83sec
Source: Myschool Past Questions Archive (Record #28551)