make u the subject in x =\(\frac{2u-3}{3u + 2}\)
A
u = \(\frac{2x + 3}{3x - 2}\)
B
u = \(\frac{2x - 3}{3x - 2}\)
C
u = \(\frac{2x + 3}{2 - 3x}\)
D
u = \(\frac{2x + 3}{3x + 2}\)
Verified Correct Answer: C.
Step-by-Step Mathematical Solution
x =\(\frac{2u-3}{3u + 2}\)
cross multiply
x(3u + 2) = 2u - 3
3ux + 2x = 2u - 3
collect like terms of u
2x + 3 = 2u - 3ux
\(\frac{2x + 3}{2 - 3x}\) = u
Source: WAEC / JAMB / NECO Classroom Archive (Record #61200)