A wave of frequency 10Hz forms a stationary wave pattern in a medium where the velocity is 20cms-1. The distance between adjacent nodes is
A
1.0cm
B
1.5cm
C
2.0cm
D
5.0cm
Verified Correct Answer: A.
Physical Principles & Numerical Solution
\(\lambda\) = \(\frac{v}{f}\)
= \(\frac{20}{10}\)
= 2cm ; distance between adjacent nodes
= 2cm \ 2
= 1cm
Source: Myschool Past Questions Archive (Record #28535)