A 1000kg elevator is descending vertically with an acceleration of 1.0ms-2, if the acceleration due to gravity is 10ms-2, the tension in the suspending cable is
A
1.0N
B
10.0N
C
9000.0N
D
11 000N
Verified Correct Answer: C.
Physical Principles & Numerical Solution
T = , m = 1000kg, a = 1\(ms^{-1}\), g = 10\(ms^{-2}\)
W - T = ma
T = W - ma
T = mg - ma
T = m( g - a )
T = 1000( 10 - 1) = 1000 x 9 = 9000N.
Source: Myschool Past Questions Archive (Record #28493)