Make q the subject of the relation t = √(pq/r - r\(^2\)q)
A
q = \(\frac{rt^2}{(p - r^3)}\)
B
q = \(\frac{t^2}{(p - r^2)}\)
C
q = \(\frac{rt}{(p - r^3)}\)
D
q = \(\frac{(p - r^3)}{rt^2}\)
E
q = rt\(^2\)(p - r\(^3\))
Verified Correct Answer: A.
Step-by-Step Mathematical Solution
t = \sqrtpq/r - r\(^2\)q
multiply both sides by the L.C.M, r
r\(^2\) = pq - qr\(^3\)
collect like terms on the RHS
q(p - r3) = rt\(^2\)
q = \(\frac{rt^2}{(p - r^3)}\)
Source: WAEC / JAMB / NECO Classroom Archive (Record #23862)