A pool of water appears to be 1.0m deep when viewed vertically from above. If the refractive index of water is 1.33, what is the actual depth of the pool?
A
0.750m
B
1.013m
C
1.330m
D
13.3000m
Verified Correct Answer: C.
Physical Principles & Numerical Solution
n = \(\frac{\text {real depth}}{\text{apparent depth}}\)
1.33 = \(\frac{\text {real depth}}{1}\)
real depth = 1.33cm
Source: Myschool Past Questions Archive (Record #28462)