2x - 3y = -11 --- (i) 3x + 2y = 3 --- (ii) Multiply equation (i) by 3 and equation (ii) by 2 6x - 9y = -33 --- (iii) 6x + 4y = 6 --- (iv) Subtract equation (iii) from (iv) 13y = 39 y = \(\frac{39}{13}\) = 3 substitute (3) for y in equation (ii) 3x + 2(3) = 3 3x + 6 = 3 3x = 3 - 6 3x = -3 x = \(\frac{-3}{3}\) = - 1 Now, \((y - x)^2 = (3 - (-1))^2\) = \((3 + 1)^2\) = \(4^2\) = 16