A cube of side 10cm and mass 0.5kg floats in a liquid with only \(\frac{1}{5}\) of its height above the liquid surface. What is the relative density of the liquid?
A
0.125
B
0.250
C
0.625
D
2.500
Verified Correct Answer: C.
Physical Principles & Numerical Solution
Height below liquid = 1 - \(\frac{1}{5}\) = \(\frac{4}{5}\)
volume of cube = 10\(^3\)cm\(^3\)
volume of liquid displaced = \(\frac{4}{5}\) x 1000
= 800cm\(^3\)
density of liquid displaced;
= \(\frac{500}{800}\)
= 0.625
Source: Myschool Past Questions Archive (Record #28410)